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9n^2=54
We move all terms to the left:
9n^2-(54)=0
a = 9; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·9·(-54)
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*9}=\frac{0-18\sqrt{6}}{18} =-\frac{18\sqrt{6}}{18} =-\sqrt{6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*9}=\frac{0+18\sqrt{6}}{18} =\frac{18\sqrt{6}}{18} =\sqrt{6} $
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